3x-8=2x^2+7

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Solution for 3x-8=2x^2+7 equation: 



3x-8=2x^2+7

We move all terms to the left:

3x-8-(2x^2+7)=0

We get rid of parentheses

-2x^2+3x-7-8=0

We add all the numbers together, and all the variables

-2x^2+3x-15=0

a = -2; b = 3; c = -15;
Δ = b2-4ac
Δ = 32-4·(-2)·(-15)
Δ = -111
Delta is less than zero, so there is no solution for the equation

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